include<stdio.h>intmain(void){puts("請(qǐng)輸入字符");if(getchar()=='A'){putchar('B');}return0;}
c=aa=bb=c
b=a;printf("d\n",b);
1、借助中間變量完成，此方法直觀，易理解，使用最多2、不需要中間變量，通過變量身的運(yùn)算完成交換。參考代碼：方法1：inta=2,b=3,t;t=a;//先將a存儲(chǔ)到臨時(shí)變量t中a=b;//將b存儲(chǔ)到a中b=t;//將臨時(shí)變量...
h>intmain(){inta,b,t;scanf("%d%d",&a,&b);printf("a=%d,b=%d\n",a,b);t=a;a=b;b=t;printf("a=%d,b=%d\n",a,b);}這道題關(guān)鍵是利用第三者作為介質(zhì)進(jìn)行數(shù)據(jù)交換...
a=a-b;}voidswap3(int&a,int&b)//使用位運(yùn)算也可以交換兩個(gè)值{a=a^b;b=a^b;a=a^b;}voidmain1mianshiti7(){inta1=1,b1=2;inta2=10,b2=15;inta3...
intmain(void){charch;printf("Pleaseinputacharacter:");ch=getchar();if((ch>='a'&&ch<'z')||(ch<'Z'&&ch>='A'))putchar(ch+1);elseif(ch=='z')pu
intmain(){inta[4][4]={{1,2,3,4},{5,6,7,8},{9,10,11,12},{13,14,15,16}};inti,j,b[2][8];for(i=0;i<4;i++)for(j=0;j<4;j++)b[i/2][i%2*4+j%4]=a[i][j]...
給你個(gè)答案參考一下：include<stdio.h>voidexchange(int*x,int*y);//此處將函數(shù)返回類型修改為void型，因?yàn)楹瘮?shù)本來就沒返回值。參數(shù)全部改為指針型。intmain(void){inta,b;printf("請(qǐng)輸入a,b\n");scanf...
include<stdio.h>intmain(){charc;do{scanf("%c",&c);if(c>'a'&&c<='z')c-=32;printf("%c",c);}while(c!='\n');return0;}
2024/6/18