Oraclerownum案例解說

選擇表中的某一行記錄：(理解：rownum是oracle系統(tǒng)順序分配為從查詢返回的行的編號(hào))select * from (select rownum a,t.* from te

選擇表中的某一行記錄：(理解：rownum是Oracle系統(tǒng)順序分配為從查詢返回的行的編號(hào))
select * from (select rownum a,t.* from testtab t) where a=2;
select * from (select rownum a,t.* from testtab t) where a=3;
select * from (select rownum a,t.* from testtab t) where a=4;
不能為：
select * from (select rownum,t.* from testtab t) where rownum=2;或
select * from testtab where rownum=2;
返回多行記錄：
select * from testtab where rownum<=10;
返回某段記錄：(如取記錄表中4-10行)
select * from (select rownum no,testtab.* from testtab where rownum<=10) where no>=4;
返回有條件且經(jīng)過排序的某段記錄：
select rownum num1,tt.* from
(select rownum num,t.* from
(select EcodeInfo.* from EcodeInfo where a=1 order by ecode desc) t) tt
where num>19 and rownum<20>
以為oracle是先提取記錄再排序的，而oracle的rownum是在提取記錄就已經(jīng)生成，，它先于排序操作，所以必須使用子查詢先排序。
不能為：
select * from tsettab where rownum>10;
返回最后一行記錄:
select * from (select rownum a,t.* from testtab t) where a=(select count(*) from testtab);
返回最后N行記錄：
select * from (select rownum a,t.* from testtab t) where a=(select count(*)-N from testtab);

----------------
select * from adminrole where rownum<=4
minus
select * from adminrole where rownum<2>

select * from
(select rownum row_id ,b.* from (select a.* from sorttable a order by sortid)b)
where row_id between 5 and 9;

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