Oracle11gR2全表掃描成本計(jì)算(工作量模式-workload)

測(cè)試了非工作量模式下Oracle11gR2全表掃描的成本計(jì)算，現(xiàn)在測(cè)試一下在工作量模式下Oracle11gR2全表掃描的成本計(jì)算首先講表blocks

測(cè)試了非工作量模式下Oracle11gR2全表掃描的成本計(jì)算，現(xiàn)在測(cè)試一下在工作量模式下Oracle11gR2全表掃描的成本計(jì)算

首先講表blocks增加到10003個(gè)

SQL> select owner,blocks from dba_tables where table_name='TEST' and owner='TEST';

OWNER BLOCKS
------------------------------ ----------
TEST 10003

然后人工設(shè)置工作量的CPUSPEED=2500，單塊讀等于5，，多塊讀等于30，MBRC等于12

SQL> begin
dbms_stats.set_system_stats('CPUSPEED',2500);
dbms_stats.set_system_stats('SREADTIM',5);
dbms_stats.set_system_stats('MREADTIM',30);
dbms_stats.set_system_stats('MBRC',12);
end;
/ 2 3 4 5 6 7

PL/SQL procedure successfully completed.

利用explain plan得到CPU_COST---這里等于 72735764

SQL> explain plan for select count(*) from test;

Explained.

SQL> select cpu_cost from plan_table;

CPU_COST
----------
72735764

成本計(jì)算公式如下：

Cost = (
#SRds * sreadtim +
#MRds * mreadtim +
CPUCycles / cpuspeed /1000
) / sreadtime

#SRds - number of single block reads
#MRds - number of multi block reads
#CPUCyles - number of CPU cycles

sreadtim - single block read time
mreadtim - multi block read time
cpuspeed - CPU cycles per second

Cost = (
#SRds * sreadtim + ---SRds=0
#MRds * mreadtim + ---MRds=BLOCKS/MBCR=10003/12, mreadtim=30
CPUCycles / cpuspeed / 1000 ---CPUCycles=PLAN_TABLE.CPU_COST,cpuspeed=2500
) / sreadtime

所以人工計(jì)算的成本等于：

SQL> select ceil(10003/12*30/5)+ceil(72735764/2500/5/1000)+1 from dual;

CEIL(10003/12*30/5)+CEIL(72735764/2500/5/1000)+1
------------------------------------------------
5009

SQL> set autot trace
SQL> select count(*) from test;

Execution Plan
----------------------------------------------------------
Plan hash value: 1950795681

-------------------------------------------------------------------
| Id | Operation | Name | Rows | Cost (%CPU)| Time |
-------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 1 | 5009 (1)| 00:00:26 |
| 1 | SORT AGGREGATE | | 1 | | |
| 2 | TABLE ACCESS FULL| TEST | 10000 | 5009 (1)| 00:00:26 |
-------------------------------------------------------------------

人工計(jì)算的cost正好等于Oracle計(jì)算的Cost 這里也說明Oracle11gR2 在工作量模式下，全表掃描的成本計(jì)算方法依然同Oracle9i,Oracle10g

工作量模式下，從全表掃描的成本可以看出，參數(shù)db_file_multiblock_read_count 的更改對(duì)全表掃描成本計(jì)算沒有影響，有影響的是MBRC，舉個(gè)例子：

SQL> show parameter db_file_multiblock_read_count

NAME TYPE VALUE
------------------------------------ ----------- ------------------------------
db_file_multiblock_read_count integer 16

SQL> set autot trace
SQL> select count(*) from test;

Execution Plan
----------------------------------------------------------
Plan hash value: 1950795681

-------------------------------------------------------------------
| Id | Operation | Name | Rows | Cost (%CPU)| Time |
-------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 1 | 5009 (1)| 00:00:26 |
| 1 | SORT AGGREGATE | | 1 | | |
| 2 | TABLE ACCESS FULL| TEST | 10000 | 5009 (1)| 00:00:26 |
-------------------------------------------------------------------

SQL> alter session set db_file_multiblock_read_count=32;

Session altered.

SQL> select count(*) from test;

Execution Plan
----------------------------------------------------------
Plan hash value: 1950795681

-------------------------------------------------------------------
| Id | Operation | Name | Rows | Cost (%CPU)| Time |
-------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 1 | 5009 (1)| 00:00:26 |
| 1 | SORT AGGREGATE | | 1 | | |
| 2 | TABLE ACCESS FULL| TEST | 10000 | 5009 (1)| 00:00:26 |
-------------------------------------------------------------------

可以看到更改db_file_multiblock_read_count對(duì)于成本沒有任何影響，因?yàn)楣ぷ髁磕Ｊ较碌腃OST只跟MBRC有關(guān)。

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